m^2-3m-11=0

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Solution for m^2-3m-11=0 equation: 



m^2-3m-11=0

a = 1; b = -3; c = -11;
Δ = b2-4ac
Δ = -32-4·1·(-11)
Δ = 53
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{53}}{2*1}=\frac{3-\sqrt{53}}{2}
$


$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{53}}{2*1}=\frac{3+\sqrt{53}}{2}
$

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